Electromagnetism

How to Calculate Resistance in a Series Circuit (Formula, Steps & Examples) 2026

A admin September 18, 2026 12 min read
How to Calculate Resistance in a Series Circuit (Formula, Steps & Examples) 2026

Need the total resistance of resistors wired end to end? Add their values together. That one rule is the core of how to calculate resistance in a series circuit.

Table of Contents

How to Calculate Resistance in a Series Circuit? The Series Resistance Formula

Definition: In a series circuit, the total (equivalent) resistance equals the sum of all individual resistances.

R_total = R₁ + R₂ + R₃ + … + Rₙ

Example: 10 Ω + 22 Ω + 47 Ω = 79 Ω.

Convert every value to the same unit before adding. Ohms (Ω) are the standard choice.

Key Takeaways

What Is a Series Circuit?

A series circuit connects components one after another along a single path. Charge has nowhere else to go, so it passes through every component in turn.

One Path for Current

Picture a garden hose with several narrow sections joined in a row. All the water must pass through each section. Electric current behaves the same way in a series circuit.

Same Current, Shared Voltage

Current is identical at every point in the loop. Voltage is different. Each resistor uses up part of the battery’s voltage, and those parts add up to the supply voltage.

Why Resistance Adds Up

Resistance depends on a conductor’s length, cross-section and material. Joining resistors end to end works like making one longer conductor.

A longer path means more opposition to current, so the values simply add.

Series Resistance Formula Explained

The formula works for any number of resistors. Two resistors give R₁ + R₂. Ten resistors give R₁ + R₂ + … + R₁₀.

Symbols and Units

SymbolMeaningUnit
R_total (or R_eq)Equivalent resistance of the whole series stringohm (Ω)
R₁, R₂, … RₙIndividual resistor valuesohm (Ω)
VSource voltagevolt (V)
ICircuit currentampere (A)
PPowerwatt (W)

Resistance Unit Conversions

UnitEqualsExample
1 Ω1 Ω470 Ω
1 kΩ (kilohm)1,000 Ω4.7 kΩ = 4,700 Ω
1 MΩ (megohm)1,000,000 Ω0.1 MΩ = 100,000 Ω

How to Calculate Resistance in a Series Circuit Step by Step

Follow these five steps for any series resistor circuit.

Step 1: Confirm the Resistors Are Truly in Series

Trace the current path. Resistors are in series only if the same current must pass through each one. If a wire branches off between two resistors, they are not in series.

Step 2: List Every Resistance Value

Write down R₁, R₂, R₃ and so on. Read the values from the schematic, the resistor color bands or a multimeter.

Step 3: Convert to the Same Unit

Change kΩ and MΩ values into ohms. For example, 2.2 kΩ becomes 2,200 Ω.

Step 4: Add the Values

Apply R_total = R₁ + R₂ + R₃ + … + Rₙ. Keep the units consistent as you add.

Step 5: Sanity-Check the Answer

The total must be larger than your biggest single resistor. If it is smaller, you probably used the parallel formula by mistake.

How to Read Resistor Values Before You Add Them

Most through-hole resistors use color bands. The first two bands give digits, the third is a multiplier and the fourth is tolerance.

ColorDigitMultiplier
Black0×1
Brown1×10
Red2×100
Orange3×1,000
Yellow4×10,000
Green5×100,000
Blue6×1,000,000
Violet7×10,000,000
Gray8×100,000,000
White9×1,000,000,000

Gold means ±5% tolerance and silver means ±10%. A brown-black-red-gold resistor is 10 × 100 = 1,000 Ω (1 kΩ) at ±5%.

Worked Examples: Calculating Series Resistance

Example 1: Three Resistors in Series

Find the total resistance of 10 Ω, 22 Ω and 47 Ω resistors in series.

R_total = 10 + 22 + 47 = 79 Ω

The answer is larger than 47 Ω, so it passes the sanity check.

Example 2: Kilohm Resistors With a 9 V Battery

Three resistors of 3 kΩ, 10 kΩ and 5 kΩ sit in series with a 9 V battery.

R_total = 3 + 10 + 5 = 18 kΩ (18,000 Ω)

Current: I = V ÷ R = 9 V ÷ 18,000 Ω = 0.5 mA

Example 3: Mixed Units

Add 470 Ω, 1.5 kΩ and 2.2 kΩ.

Convert first: 470 Ω + 1,500 Ω + 2,200 Ω = 4,170 Ω, or 4.17 kΩ.

Adding 470 + 1.5 + 2.2 directly would give a meaningless number.

Example 4: Finding a Missing Resistor

A 9 V source drives 0.25 A through R₁ = 12 Ω, R₂ = 8 Ω and an unknown R₃.

First find the total: R_total = V ÷ I = 9 ÷ 0.25 = 36 Ω.

Then subtract: R₃ = 36 − 12 − 8 = 16 Ω.

Example 5: Identical Resistors Shortcut

When all resistors match, multiply instead of adding. Six 33 Ω resistors in series give:

R_total = n × R = 6 × 33 = 198 Ω

Example 6: Building a Non-Standard Value

You need about 150 Ω for an LED on a 5 V supply. Assume the LED drops 2 V at 20 mA.

Required resistance: R = (5 − 2) ÷ 0.020 = 150 Ω.

If you lack a 150 Ω part, join 100 Ω and 47 Ω in series for 147 Ω. The current becomes 3 ÷ 147 ≈ 20.4 mA, which is close enough.

Using Ohm’s Law With Series Resistance

Once you know R_total, Ohm’s law unlocks everything else. Use it for current, voltage drops and power.

Finding the Circuit Current

Divide the supply voltage by R_total. In Example 1 with a 12 V battery: I = 12 ÷ 79 ≈ 0.152 A.

This same current flows through all three resistors.

Finding the Voltage Drop Across Each Resistor

Multiply the shared current by each resistor’s value.

ResistorValueCurrentVoltage drop (V = I × R)Power (P = I²R)
R₁10 Ω0.152 A1.52 V0.23 W
R₂22 Ω0.152 A3.34 V0.51 W
R₃47 Ω0.152 A7.14 V1.08 W
Total79 Ω0.152 A12.00 V1.82 W

Checking With Kirchhoff’s Voltage Law

Kirchhoff’s voltage law says the voltage drops around a loop equal the source voltage. Here, 1.52 + 3.34 + 7.14 = 12.00 V. The numbers agree.

Calculating Total Power

Total power can be found three ways: P = V × I, P = I² × R_total or P = V² ÷ R_total. All give about 1.82 W here.

The total power dissipated in the resistors equals the power supplied by the source. That reflects conservation of energy.

The Voltage Divider Rule

A quick way to find one resistor’s share of the voltage: V_x = V_source × (R_x ÷ R_total).

With 12 V across a 10 kΩ and a 20 kΩ resistor, the 20 kΩ resistor gets 12 × 20 ÷ 30 = 8 V.

How to Measure Resistance in a Series Circuit With a Multimeter

You can confirm your calculation with a digital multimeter set to the ohms (Ω) range.

  1. Turn off and disconnect the power source completely.
  2. Set the multimeter to the ohms range.
  3. Touch the probes to the two outer ends of the series string.
  4. Read the display and compare it with your calculated R_total.

Measure with power off, or the reading will be wrong and the meter can be damaged. Also remember that other parts of the circuit connected across the string can distort the reading. Isolate the resistors if needed.

Series vs Parallel Resistance

FeatureSeries circuitParallel circuit
Current pathOne single pathMultiple branches
CurrentSame through every resistorSplits among branches
VoltageDivides among resistorsSame across every branch
Total resistance formulaR₁ + R₂ + … + Rₙ1/R_total = 1/R₁ + 1/R₂ + … + 1/Rₙ
Total vs individualLarger than the biggest resistorSmaller than the smallest resistor
If one component fails openWhole circuit stopsOther branches keep working
Typical useCurrent limiting, voltage dividersHousehold outlets, lighting circuits

Series-Parallel (Mixed) Circuits

Real circuits often combine both arrangements. Simplify them in stages. Reduce each obvious series group or parallel group to a single equivalent value, then repeat.

Example: R₁ = 100 Ω is in series with a parallel pair of 200 Ω and 300 Ω.

Parallel pair: (200 × 300) ÷ (200 + 300) = 120 Ω.

Total: 100 + 120 = 220 Ω.

Resistor Tolerance and Real-World Accuracy

Real resistors are not exact. A ±5% resistor can be off by 5% in either direction.

For Example 1 (79 Ω), the worst-case range with 5% parts is 79 × 0.95 = 75.05 Ω to 79 × 1.05 = 82.95 Ω.

Use 1% parts when precision matters, such as in voltage dividers for sensors. Series strings also average out some random error, since not every resistor is off in the same direction.

Battery Internal Resistance (Advanced)

Real batteries have a small internal resistance (r) that acts in series with your circuit.

The full current is I = V ÷ (R_total + r). With a 12 V battery, r = 0.5 Ω and R_total = 79 Ω, I = 12 ÷ 79.5 ≈ 0.151 A.

The terminal voltage falls to about 12 − (0.151 × 0.5) ≈ 11.92 V.

Do the Series Rules Apply to Other Components?

Not every component follows the same rule, so check before you add.

Component in seriesRule
ResistorsAdd: R_total = R₁ + R₂ + …
Inductors (no coupling)Add: L_total = L₁ + L₂ + …
CapacitorsReciprocals add: 1/C_total = 1/C₁ + 1/C₂ + …
Batteries (same direction)Voltages add
Diodes and LEDsNot fixed resistors, so use their forward voltage instead

Real-World Uses of Series Resistance

Common Mistakes to Avoid

MistakeWhy it is wrongFix
Using the parallel (reciprocal) formulaIt gives a total smaller than any resistorSimply add the values in series
Mixing kΩ and ΩThe sum is off by a factor of 1,000Convert everything to ohms first
Using total voltage with one resistor’s valueThe result matches nothing real in the circuitUse V_total with R_total, or V_R with R
Measuring with power onGives false readings and can damage the meterDisconnect power first
Ignoring toleranceThe real value can differ from the labelCheck the tolerance band
Forgetting battery internal resistancePredicted current is slightly too highAdd r to R_total when accuracy matters
Assuming parts are in series when a branch existsCurrent is not the same through both partsTrace the path and look for junctions

Expert Tips

Practice Problems

Try these, then check the answers below.

  1. Find R_total for 100 Ω, 220 Ω and 330 Ω in series.
  2. Find R_total for 1.2 kΩ, 4.7 kΩ and 680 Ω in series.
  3. A 12 V battery drives current through a total series resistance of 600 Ω. What is the current?
  4. The measured total is 48 Ω. R₁ = 18 Ω and R₂ = 12 Ω. Find R₃.
  5. Five identical 68 Ω resistors are in series. What is R_total?

Answers

  1. 650 Ω
  2. 1,200 + 4,700 + 680 = 6,580 Ω (6.58 kΩ)
  3. I = 12 ÷ 600 = 0.02 A (20 mA)
  4. R₃ = 48 − 18 − 12 = 18 Ω
  5. 5 × 68 = 340 Ω

Also Read:

Frequently Asked Questions (FAQs)

What is the formula for resistance in a series circuit?

R_total = R₁ + R₂ + R₃ + … + Rₙ. Add every resistor’s value, using the same unit for all of them.

How do you find total resistance in a series circuit with 3 resistors?

Add the three values. For 10 Ω, 22 Ω and 47 Ω, the total is 79 Ω.

Why does resistance add up in a series circuit?

Charge must pass through every resistor in turn. Each one adds its own opposition, much like lengthening a single conductor.

Is total resistance bigger or smaller in a series circuit?

It is bigger. The total is always greater than the largest individual resistor.

How do you calculate resistance in a series circuit with voltage and current?

Use Ohm’s law rearranged: R_total = V ÷ I. If a 9 V source drives 0.25 A, the total is 36 Ω.

Is current the same everywhere in a series circuit?

Yes. There is only one path, so the same current flows through every component.

How do you find the voltage across each resistor in series?

Multiply the shared current by each resistor’s value (V = I × R). You can also use the voltage divider rule.

What happens to total resistance when you add another resistor in series?

The total increases by exactly that resistor’s value. Current from a fixed voltage source then drops.

How do you calculate series resistance with different units?

Convert all values to ohms first. For example, 2.2 kΩ becomes 2,200 Ω before you add it to any ohm values.

What is the difference between series and parallel resistance?

In series, resistances add and the current is shared. In parallel, reciprocals add and the voltage is shared, so the total is smaller than any branch.

Can I use the series resistance formula for capacitors?

No. Capacitors in series follow a reciprocal rule: 1/C_total = 1/C₁ + 1/C₂ + …. Inductors in series do add, like resistors.

How do you find a missing resistor in a series circuit?

Find R_total from V ÷ I, then subtract the known resistors. The remainder is the unknown value.

How many resistors can you connect in series?

There is no theoretical limit. In practice, the supply voltage and power ratings decide how many make sense.

What is equivalent resistance?

It is the single resistor value that would draw the same current from the same source as the whole combination.

How do you measure resistance in a series circuit?

Turn the power off, set a multimeter to ohms and measure across the two ends of the series string.

Does wire resistance matter in a series circuit?

Usually not. Connecting wires have far less resistance than the load, so they are treated as ideal in most calculations.

What happens if one resistor fails open in a series circuit?

The circuit is broken, current stops and every component in the loop goes off.

How do you calculate power in a series circuit?

Use P = V × I for the total, or P = I² × R for each resistor. The individual powers add up to the total.

How do you calculate resistance in a series-parallel circuit?

Reduce each parallel group to one equivalent value, then add the series parts. Repeat until one value remains.

Do identical resistors in series share voltage equally?

Yes. Equal resistances carry the same current, so each drops the same voltage: V_source ÷ n.

Why are household outlets wired in parallel instead of series?

Parallel wiring gives every appliance the full supply voltage. Each device also works independently of the others.

Conclusion

To calculate resistance in a series circuit, convert all values to ohms and add them. The result is always larger than your biggest resistor.

From there, Ohm’s law gives you the current, each voltage drop and the power. Checking that the drops add up to the supply voltage confirms your work.

Practice with the problems above, then test yourself using the Ohm’s Law Calculator and explore the rest of the site to keep building your physics skills.

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Physics educator and contributor at Physics Fundamentals.

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